#include<stdio.h> #include<conio.h> void main() { int a,b,opt; l: printf("enter the following option"); printf("\n1.add\n2.asub\n3.mul\n4.exit"); scanf("%d",&opt); if(opt==1) { printf("enter first operand"); scanf("%d",&a); printf("enter second operand"); scanf("%d",&b); printf("a+b=%d",a+b); } else if(opt==2) { printf("enter the 1operand"); scanf("%d",&a); printf("enter 2nd operand"); scanf("%d",&b); printf("a-b=%d",a-b); } else if(opt==3) { printf("enter the 1st value"); scanf("%d",&a); printf("enter the 2nd value"); scanf("%d",&b); printf("\n a*b=%d",a*b); } else if(opt==4) exit(0); else printf("\nwrong option\n"); goto l; getch(); }
C Program For Arithmetic Calculator using if else ladder(2 operands 1 operator frm user)
January 02, 2015
By:
Bhanu Namikaze
Bhanu Namikaze
Bhanu Namikaze is an Ethical Hacker, Security Analyst, Blogger, Web Developer and a Mechanical Engineer. He Enjoys writing articles, Blogging, Debugging Errors and Capture the Flags. Enjoy Learning; There is Nothing Like Absolute Defeat - Try and try until you Succeed.
1 comment:
good work bro but you put the longer way to do the programming
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